Can you show the URL you are using with sqlalchemy?

The url is

f'postgresql://user:password@/db_name?host=/cloudsql/project-name:region:instance-name&port=5432'

so host is

/cloudsql/project-name:region:instance-name

but I have to make a workaround to pass host additionally as a kwarg, so asyncpg.connection. connect receives dsn and host as above as host from the kwargs takes precedence.

It could be either

f'postgresql://user:password@/db_name?host=/cloudsql/project-name:region:instance-name:5432'

the result is similar.
but it's parsed as

host = "/cloudsql/project-name"
port = "region:instance-name:5432"

Bumping this - am having the exact same issue.

Try URL encoding the colons?

Hi there,

I'm trying to figure the state of this issue and it's not clear to me. Are we able to pass the CloudSQL /cloudsql/<project>:<region>:<db_instance> format? I tried to urlencode but I'm getting the same issue that actual string is not kep as it should.

Looking through the code a bit more. It seems the logic is to assume Host:Port from the get go (and call _parse_hostlist). Maybe a check before calling that function for the host starting with a /? Or change its name and make the check from within?

This is working now in the latest version (with #470), maybe someone can close this ticket to avoid confusion?

awesome news @maxzheng!

Hi @maxzheng Can you tell me in detail how you made it work? I have been trying:

postrgres://user:passw@/cloudsql/projectId:region:instance-name/postgres (dbname)